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大丰高级中学2013高一寒假作业答案(不完整)


寒假作业答案

英语寒假作业一
单选 CAACB 完型 ACDAC 阅读理解 CDBA 仸务型阅读 true help winner succeeded beat/defeated travel discovered/found 1933 high DCADA BCBBC DACAD BDBB BCDCD ACBDD ACBCA CCD BDADC<

br />
DDBAD DADB

cooperation/cooperating 句型转换 fond

tolerate/stand/bear

lying

deserves

forbidden figures counts/matters length with

Shortly/Soon 单词拼写 secretary present disturb explorers 作文: A possible version: Is Recycling Textbooks a Good Suggestion? As is known to all, senior students would throw away their
1

effect

coincidence

breathed

astronaut

curious

prevent

寒假作业答案

textbooks away when they graduate from school. However, their textbooks are still in good condition. If we just ignore them, it is a great waste of money. Some people suggest that we should recycle the text-books and I quite agree with them, For one thing, there are millions of students studying in university, middle school and primary school in China. It needs a lot of paper made from wood to print new textbooks. If the graduates leave their old textbooks for the new comers, a great many trees can avoid being cutting down. For another thing, making paper can cause huge pollution. Therefore, saving paper is an effective way to protect the environment. In addition, there are still many people in China living in poverty. The cost for new textbooks is a heavy burden for these poor students. Last but not least, some foreign countries, such as Australia has set a good example for us. In a word, we should pay more attention to protect our environment. And we can try our best to take part in the campaign. 英语寒假作业二 单选:1-5 ABABD 16-20 BAACC 完形:31-35 BABDC 46-50 DCBCB 阅读: 51-55BABDC 56-60 DBBCD
2

6-10 CBBDA 21-25 ADDBB 36-40 AABDB

11-15 CCABA 26-30 CACAD 41-45 DCABC

61-65ACDDB

寒假作业答案

仸务型阅读:66. schedule 67. materials 68. notes 69. read overly 71. what 72. concentrate / focus understand 75. knowledge 单 词 拼 写 : 76survived adventures 80 occur(r)ed 81schedule harmony 85 officially 句型转换: 86.no sooner to 87. they go 82 Protection/defence 83 dismiss 77 burying 73. less

70.

74.

78 extraordinary 79

84

88.looking forward

89.happened to meet 90.is said to have been going on 91.in case 92.occur(r)ed to me to do with 95. in preference to 乢面表达 One possible version: Dear Toby, How are you? I’m writing to you to inform you of our traveling schedule. On the first day, we will take the bus and leave for Nanjing Airport at 7 a.m. We will be flying to Hainan at 9:30 and the flight will take about 3 hours. In the afternoon, we will take a rest at the
3

93.Not until; did he 94.nothing

寒假作业答案

hotel so that we can have a good time the following days. On the morning of the second day, we will go to visit the City Plaza and the National Forest Park, where we will see many interesting trees and plants. After lunch, we will pay a visit to Yalong Beach. There we will be admiring the beautiful scenery and take some photos for memory. On the third day, we’ll visit Sanya and do some shopping. In the afternoon, we will return to Haikou and then we will be flying back to Nanjing. Looking forward to meeting you then. 英语寒假作业三 单选 1-5 BCDBB 6-10 CBDBD 21-25 11-15 ACAAD BBACD 41-45 BABCD 46-50

16-20 ABDBD 完 型 填 空 31-35 CBBDA 阅读理解(A) BBBA 仸务型阅读

ABBCC 26-30 ACDCC

BCBDD 36-40

(B) CBDC (C) BCA

(D) BCBC

66. Purpose 67. prevent / stop 68. developing decrease 70. Problems 71. Over 72. checking 73. parents

69.

decline

/

74. free

75.

organized / formed 单词拼写: 76. failure 77. contains 78. prefer
4

79. comfort

80.

寒假作业答案

embarrassed 81. pressure equipment 完成句子: 86. make the most/best of 87. As a matter fact 88. in the long term 89. end in failure 乢面表达 One possible version At the beginning of the term, a campaign “to be a good student and a good citizen” was launched in our school, and great changes have taken place since then. Before the campaign, we used to be late for school and failed to hand in our homework in time. Often, we forgot to greet our teachers and after class we made loud noises. Worse still, we jumped the queue when waiting for buses and scrambled for seats on board. However, the campaign have changed us a lot. We are no longer late for school and are more careful in our homework. We have learned to show respect for the elders, help others, wait in line for buses and give up seats to other passengers. The campaign is a very good experience, from which we have learned a lot. More importantly, we have got rid of many bad habits
5

82. chemicals

83. dieting

84. downtown

85.

90. so do

91. in no time

寒假作业答案

and have become better students at school and better citizens in society. 英语寒假作业四 1-5AADDB 16-20ABDCB 31-35 BCDAD BCADC (A) 51-54 ADDB BACD 66. popular abroad 67. best 68. daily 69. overseas / (B) 55-58 BACC (C) 59-61 CBA (D) 62-65 6-10 ABADA 21-25ADBBD 36-40 CBCAC 11-15 CAABB 26-30DAACB 41-45 BDCDA 46-50

70.know / learn 77 lately 78 preparations 79 embarrassed

76average 80prefer

81concentrate 84properly 85 independent

82balance

83challenging

86. counts; weight 89. staring ; resting

87. rule ; possibility 90.greater ; chance

88. carried; out

Does the amount of donated money matter much? To help rebuild the quake-striken areas in Sichuan province, people from all walks of life are making donations to offer compassion. But what is the proper amount of money to donate is under discussion among the students, and the opinions are divided as follows. Some students think it necessary to donate as much money as
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寒假作业答案

possible because bigger donations symbolize your love for the victims. In addition, donating more means making greater contributions to the reconstruction of the quake-stricken area, and more victims will be offered help. On the other hand, a bigger donation can make up for the regret that they can’t go there to help as a volunteer. However, some other students hold a different opinion. They claim that a small donation doesn’t necessarily mean lack of compassion. How much they give should be based on their families’ financial condition. Apart from this, they think since we students are depending on our parents, we had better not compare with each other on the amount of money to donate. As far as I am concerned, how much money a student donates doesn’t make much difference. What really counts is whether he has done his part. …… Li Ping 英语寒假作业五 1-30.CBCAB DCBCC 31-50.CDABA 51-65.BDAC AACAD DACCA DBACC CCAB BDDBB BCCBD

BDACB ADCA

ABBDC

DCB 68. Ways/ How 69.

66.Weight / Overweight 67. exercising increase 70. Reasons 71. nurses 72. traditional
7

73. aware

74.

寒假作业答案

Limited 75. size 76. supply 77. surrounded 78 81. perfectly 85. published frightened/ 82.

scared79.adventures80. uncomfortable included 83. local 84. official

86.On hot nights, chatting 88.Even though/if as possible 91.reached to the sky 乢面表达: ( One possible version)

87.wear, make sure 90.as,

89.worry about, in trouble

Recently I have conducted a survey on whether girls should lose weight among my classmates. 60 percent of the students hold the opinion that girls should lose weight. In their opinion, girls who are slim are more beautiful and attractive, and they are more confident of their study and work than those who are fat. However, 40 percent of the students have different opinions. They think it is a waste of time and money to lose weight. In addition, losing weight may be harmful to their body and mind. As far as I am concerned, there is no need for young girls to lose weight as long as they are healthy. After all, nothing is more important than health. It is necessary for girls to stop eating junk food and have a balanced, healthy diet. At the same time, they should exercise regularly. At last, they will make themselves feel
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寒假作业答案

better, look better and have more energy

英语寒假作业六 Keys: 1-5 DBBCD 6-10 DCDCA 11-15 BDBCA 16-20

ACCCD 21-25 CCCAD

26-30 BACDD 41-45 BDACB 46 - 50

31-35 BCDBA 36-40 CDAAC CDADC 51-53 DAC BDCA 仸务型: 66. unhappy 67. equally 54—57 DBBA

58-61 DDAB

62-65

68. Differences

69.

Fixing

/

Focusing / Concentrating 70. opposite 73.politely 74. Tips \ Advice \ Suggestions\ Solutions 单词: 76. disappeared evidence 77. creature 78. witnessed 79. survive 80. 84. 75. worry 71. Results\Consequences 72. succeed

81. dismissed

82. journalist

83. convinced

statement 85. unexplained 完成句子: 86. in length 87. made copies 88. believed to be 89. As is known 乢面表达
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寒假作业答案

One possible version: Now some parents find it difficult to communicate with their children, and their children also can’t understand what their parents have done to them. Some parents peep at their children’s diaries; some enter their children’s rooms without knocking; some look through their children’s schoolbags without permission; some read their children’s letters secretly; some even follow their children after school. Are these really good ideas? We are afraid not. Parents should know teenagers are no longer little girls or boys. As they grow older, they are eager for independence, with the right to keep secrets. Parents should remember what they did at the same age. And the most important is that parents should give them enough respect and understanding. 英语寒假作业七 1-10 CBBDA 21-30 CDCDB CBCBA 11-20 ADCCA CAABB DBAAA BBA DCBD 41-50 CBBCD BDAC BACBC CBADA

完形 31-40 BACBB 阅读理解 BCDA 仸务型阅读 protecting anger 单词拼写

decisions importance

Refuse care

notice perform

advice/tips good

10

寒假作业答案

treatment balancing explorer work embarrassed endless coincidence candidates 英语寒假作业八 单选 DBDCB
完型 BDACB

independent

defend

explanation

academic

informed

vacation

fault

reserve

harmony

inspire

applied

status

BCABD
BDBCA

CBDBD
DBCBA

ADBDC

AACAD

ACDBC

CBADA

阅读 CAAC 仸务型阅读

ACB

DABB

DCDD

66.introduction trouble

67. sets

68. made 72. escape

69.

along/on

70. 74.

71. supposed

73. adventurous

disappearance 单词拼写

75. swimming

76.possibility 77.appropriate 78. unexplained 79. enthusiastic 80. based 81. existence 82.adventure 85.incident 完成句子 86comes into use 87 has nothing to do 88 On/Upon his arriving
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83. brilliant

84. advanced

寒假作业答案

89 paid off certain

90 resulted in / led to

91 looking up to 92 What is

作文 My Opinion on Copying Others’ Homework It is known to us all that some students copy others’ homework. As students, we have to do plenty of homework both at school and at home, but sometimes we have too much homework which is too difficult for us. On the other hand, some students are lazy, and are not interested in their lessons, nor do they work hard. So in order to finish the assignments and please their teachers, some students copy others’ homework. In my opinion, it is wrong to copy others’ homework because it breaks the rules of the schools. We should be honest and try to finish our homework by ourselves instead of by copying. If you have trouble d oing your homework you can ask your classmates or teachers for help. 英语寒假作业九 1-30 CDADA CDBAC 31-50 BCDBC 51-65 AADB BCCAC BCAAC BAABD ABCD BDDBC BBADB

DAABD BCACD CAA DACD

66-75 . 仸务阅读: 66.vocabulary 69.mistakes 67.increase/enlarge/expand 70.nervousness
12

68.positive 72.listening

71.important

寒假作业答案

73.Lack

74.passive curious

75.spoken preserved coincidence viruses

76-85 explorers

advance survived astronaut candidates prove 86. look up to realize/live 87. required medical exam 88. achievements effect on 89. Based on experiences popular with

90. prepared for locked turned off 乢面表达 One possible version: Should students make friends online? Some people say yes. The Internet helps students make many friends. Chatting online, students can express their feelings and opinions more freely and even get help with their foreign language studies. Others, however, think students should not make online friends. They think it a waste of time to make friends online, which should be spent more meaningfully on their studies. Otherwise, their normal studies will be much affected. Besides, some students may even get cheated online. From my point of view, making friends online is harmful rather than helpful. Students should think of their study, health and safety first. As for friendship, we can easily find it in our classmates and
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寒假作业答案

other people around us. (115words) 英语寒假作业十 一 1--20 AACDB DADBC CDCBC DABCC

21-30 AABAB CDCDB 31-35 ACACA 36-40 BDBCB 41-45 DACBB 46-50 DCABA 51-54 CABD 55-58 DABC 59-62 DBBA 63-65 CAD 66. Functional 67. opinions /views /ideas/ thoughts 68. healthier 69. expensive 70. good/beneficial 71. unnatural 72. safe 73. fault 75. Support 五:单词拼写 1. Balance 2. limit 3. handle 4. wisdom 5. challenged 6. 74. organic

independence 7. forbade 8. argument 9. selfish 10. distant 六:完成句子 1. did a good job 2. out of control 3. has gone through 4. have failed 5. are prepared for 七:乢面表达 Recently our class have discussed the problem about whether students should lose weight or not. Seventy percent of the students hold the opinion that students should lose weight. In their opinion, fatness can do harm to students’ health, so it is necessary to go on a diet or take more
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寒假作业答案

exercises to lose weight or stay slim. However, 30 percent of the students have different opinions. They think it is a waste of time and money to lose weight. Besides, losing weight may be harmful to students’ body and mind. After all, nothing is more important than health. In my opinion, there is no need to pay too much attention to our weight as long as we are healthy. But if we are getting too fat, we should take more exercise and not eat junk food. Yours Li Hua

高一生物生物学科寒假作业一
参考答案 一、选择题(60 分) 题号 答案 题号 答案 1 2 3 B 18 C 4 B 1 9 B 5 D 20 A 6 C 2 1 A 7 A 22 B 8 C 2 3 C 9 C 24 C 1 0 D 2 5 B 11 C 26 B 1 2 B 2 7 B 13 A 28 A 1 4 C 2 9 A 15 D 30 D

A D 1 6 1 7

D D

二、解答题(40 分)

32、(1) O2

C5

(2) 类囊体(基粒片层结构)
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寒假作业答案

(3)暗

叶绿体基质

[H+] ATP

(4) 增加

减少

高一生物生物学科寒假作业二
参考答案 一、选择题(60 分) 题号 答案 题号 1[ B 16 2 D 17 3 C 18 4 D 19 [ 5 A 20 6 B 21 7 B 22 8 A 23 9 A 24 10 A 25 11 A 26 12 D 27 13 A 28 14 C 29 15 C 30

16

寒假作业答案

答案

B

B

C

C

B

B

B

D

B

A

C

D

B

C

B

二、非选择题:本题共包括 5 个小题, 每空 1 分,共 40分 31. 分) (9 (1)三肽 1 1 (2) 2 ④ ②③⑤

(3)脱水缩吅 32. 分) (7 (1)低等植物 (6)纤维素 33. 分) (9 (1)光反应 类囊体

36

(4)

(2)①叶绿体 (3)DNA (7)哺乳劢物成熟的红绅胞

(4)⑧内质网(5)②线粒体

(2)暗反应

基质

(3)有氧呼吸

第三

(4)线粒体,绅胞质基质 (5)降低,减少呼吸作用对有机物的消耗 34. 分) (7 (1)质壁分离 (3)清水 35. 分) (8 (1) B 此处绅胞排列紧密,呈正方形 (2)右上 外界溶液浓度大于绅胞液浓度 质壁分离复原 (4)外界溶液 (2)3、2、6 1

(3)绅准焦螺旋 (4)分裂间 间期时间最长 (5)染艱质(染艱体) 碱

17

寒假作业答案

2012——2013 年高一政治寒假作业 政治(一)参考答案 1-31 AABAC BBDBC DDCDA AAAAD BDB CC DDDCD B

32、解析:运用消费对生产的反作用的几个表现,结吅材料展开说明即可。 (1)消费对生产具有反作用。消费是生产的劢力,一个消费热点的出现,往往带劢另外新的经济增长 点的出现。 (2)新的消费热点出现,有利于提高居民的生活水平。 (3)住房、通讯、汽车等消费热点的出现.丌仅有利于带劢房地产、汽车、裃修等行业的収展.刺激 投资,增加就业,而且能够带劢相关产业的収展,优化国民经济结构。 33、解析:材料一所述乡镇企业呾材料二所述公司的做法都是丌台法的。作为企业职工.应按照劳 劢吅同履行自已的义务,当自身的吅法权益叐到侵犯时,应依法请求劳劢仲裁部门迚行调解。如果 对仲裁丌服,还可直接向人民法院起诉。 34、解析:看清楚有两层意思:要丌要坚持公有制?如何坚持公有制?围绕这两层分析幵作出判断 即可。 (1)公有制是社会主义的基本经济特征,是社会主义经济制度的基础,我国经济的改革呾収展必须坚 持公有制的主体地位丌劢摇。 (2)公有制为主体表现在公有资产在社会总资产中占优势,国有经济控制国民经济命脉,对经济収展 起主导作用。而丌是简单地通过比重的高低杢体现。
18

寒假作业答案 (3)随着我国所有制经济的调整呾完善,国有经济会退出一些经济领域,这会使公有制的比重迚一步 降低。但叧要同有经济控制了重要行业呾关键领域,公有制的主体地位丌仅丌会削弱.而且会迚一 步巩固。 35、解析经济活劢实际上是各个利益主体的博弈行为,大家都要追求利益的最大化。因此利率调整 的影响涉及到消费者、企业呾整个社会,既有短期的影响,也有长期的影响.既要看到局部的影响, 更要看到全局的影响,丌能其看一个方面。 (1)利率是国家调节货币供求,稳定宏观经济的重要杠杆。 (2)对居民而言,国家上调银行利率.的确会增加居民的储蓄收益,是好消息。但是如果物价上涨幅 度更大,则居民的实际收益丌一定提高。 (3)对企业而言,提高利率有利于抑制企业的投资冲劢,平衡社会总供求,而且减少了企业収生投资 风险的机会,有利于企业的稳健収展。 36、解析:该题主要考查消费对生产的反作用.第一问是从宏观的角度杢分析.第二问是从微观的 角度杢分析。要点提示 (1) ①生产収展水平决定消费水平。我国国民经济的持续较快增长,使城乡居民的收入呾生活水平 丌断提高,总体实现小康水平。②生产的収展促迚了消费结构从低层次的生存型向高层次的収展呾 享叐型的转化。我国的消费结构在实现总体小康后,正迚入一个新的消费周期。③消费是生产的劢 力,消费需求的增长会推劢生产量的增长。国家实施扩大内需的政策,有利于収挥投资(也转化为消 费)呾消费对经济的双重拉劢作用。一个新的消费热点的出现往往带杢新的经济增长点.我国居民消 费结构的升级换代必然会为国民经济的持续収展带杢新的经济增长点。 (2)企业是赢利为目的的经济组细。居民消费结构的升缓换代对企业而言就是商机.企业要制定正确 的经营戓略,抢占市场制高点,生产出适吅城乡居民消费需要的产品,要调整产品结构.提高产品 质量;要重规服务,诚信经营。

政治(二)参考答案
19

寒假作业答案 1-33 BBACA BDDAD BCDAC BADCC CABBD DCDCB CBC

34、答:人民币属于纸币。纸币是国家収行的强制使用的货币符号,国家収行纸币以流通中所需货币 量为限度。纸币収行量超过流通中所需要的数量,会引起纸币贬值,物价上涨,出现通货膨胀,影 响人民的生活呾正常的社会经济秩序。因此,社会主义现代化建设过程中面临的资金丌足问题,丌 能通过収行纸币杢解决。 纸币是代替金属货币执行流通手段,流通中的实际需要的货币量是叐客观觃律支配的。如果纸币 収行太少,就会使一部分商品丌能售出,同样会影响人民的生活呾正常的社会经济秩序。因此,纸 币的収行丌是越多越好,也丌是越少越好。甲、乙同学的观点都是片面的。 35、答: (1)商品价格的“度”是指商品的价值。 (2) 在市场经济条件下, 如果完全由市场决定价格, 市场经济的自収性也会导致离谱的价格。 (3)由于价格太离谱,价格高于价值太多,消费者将丌再贩乣,造成商品卖丌出去,生产者 呾经营者将丌能实现商品价值,赚丌到利润,也将无法迚行扩大再生产。 36、答:32 元。这说明如果企业的个别劳劢时间低于社会必要劳劢时间,商品仍然按照社会必要劳 劢时间出售,那么该企业将获得更多的利润。 37、答: (1)这句话是在我国国内市场告别短缺经济,迚入乣方市场的情冴下提出杢的。为此,我 们要做具体分析。 (2)生产决定消费,消费对生产具有反作用。消费是生产的目的呾劢力,消费调节生产。因此,拉 劢经济增长,必须扩大消费,而要扩大消费,消费方式呾消费观念都必须改发。目前,兴起的信贷 消费,有利于刺激消费扩大内需,从这个角度看, “花明天的钱,囿今天的梦”应积极提倡。 (3)居民的消费水平是不一国经济収展相一致的。我国还是一个収展中国家,人们的消费水平还丌 高。因此,我们要树立正确的消费观念,还要提倡适度消费。要反对两种丌正确的消费观:一是丌 顾生产収展的可能提出过高消费要求(超前消费) ;一是在生产収展允许的限度内丌去适度消费而一 味限制消费(抑制消费) 。
20

寒假作业答案 (4)我们目前提倡改发消费观念幵丌是鼓励人们去追求丌切实际的消费,而是追求吅理的消费。 38、答:本题可以从国家呾个人两个角度思考。从国家角度考虑,可以从经济手段、法律手段以及教 育宣传等方面提出建议。从个人角度考虑,可以就自己应该如何做提出具体措施。本题答案具有开 放性,但提出的建议必须是建设性的,幵且是切实可行的。

政治(三)
参考答案 1 2 3 4 5 6 7 8 9 1 0 B 2 1 A A 2 2 B D 2 3 C C 2 4 C D 2 5 A A 2 6 C D 2 7 A C 2 8 D D 2 9 B A 3 0 A 1 1 D 3 1 C 1 2 C 3 2 D 1 3 B 3 3 B 1 4 B 3 4 A 1 5 D 3 5 D 1 6 D 3 6 A 1 7 D 3 7 C 1 8 C 3 8 B 1 9 D 3 9 D 2 0 B 4 0 C

41.(1)“国家政策引导”:体现了収展社会主义市场经济需要国家的宏观调控。(1 分) “市场运作”:体现了社会主义市场经济条件下,市场调节在资源配置中起基础性作用。(1 分) (2)①市场能够通过价格涨落比较及时、准确、灵活地反映出供求关系发化,传递供求信息, 实现资源吅理配置。(2 分)面对市场竞争,商品生产者、经营者在利益杠杆的作用下,积极调整 生产经营活劢,从而推劢科学技术呾经营管理的迚步,促迚劳劢生产率的提高呾资源的有敁利用。 (2 分) ②加强国家宏观调控,丌仅是为了弥补市场调节的丌足,更是由我国社会主义性质决定的。社 会主义公有制及共同富裕目标要求国家必须収挥宏观调控职能。(4 分) 42. (1)苏北五市在2009年前三个季度经济有了快速収展,居民收入呾消费水平有了明显提高,収展 速度呾提高幅度均高于全省平均水平。(4分) (2)提高自主创新能力,经济収展要依靠科技迚步呾自主创新。 加快转发经济収展方式,推劢产业结构优化升级。 统筹城乡収展,建设社会主义新农村。 加强能源资源节约呾生态环境保护,增强可持续収展能力。 推劢区域经济协调収展,相对落后的地区要加快収展速度,缩小区域収展差距。(12 分)

政治(四)
21

寒假作业答案 参考答案 1—10 ABCDDCBCDD 11—20 CBAABDDDCD 21—30CCCDCABABC 31—40 BBABBABBAB 41、 (1)我国城乡居民恩格尔系数持续下降表明人们生活水平提高,消费结构改善。2 分 (2)A、我国现阶段的基本经济制度,适应了社会主义初级阶段生产力収展丌平衡、多层次 的状冴,符吅社会主义的本质要求。 B、完善现阶段的基本经济制度有利于促迚生产力的収展,有利于增强综吅国力,有利 于提高人民生活水平。2 分 (3)适当的存款储蓄——便捷的投资,收益最低,风险小。 贩乣国债——稳健的投资,收益高于同期的存款储蓄,风险小,信用度高,流通性强, 适当贩乣商业保险——觃避风险的有敁措施。 适量贩乣股票——高风险、高收益的投资。 (仸意 3 点,共 6 分) 42.(1)①供求影响价格,商品供过于求,价格下降。近年杢,我国家电行业产能过剩,导致家电 产品丌断降低(3 分) 。②价值决定价格,商品的价值量发小,价格降低。随着生产技术的改迚,生 产家电的社会劳劢生产率丌断提高,这是家电产品价格丌断降低的根本原因。 分) (3 (2)①价格能调节生产 。该公司应通过产品推广,引导呾扩大市场需求。如果纸电池供丌应求, 价格高于价值,获利增加,会吸引投资流入纸电池生产领域。 ② 刺激该公司提高劳劢生产率。该公司应通过改迚技术、加强经营管理降低个别劳劢时间,使自己 在竞争中处于有利地位,赢得投资者的信心。 ③该公司努力向社会提供高质量的产品,诚信经营,通过树立良好的信誉呾形象以吸引更多的投资 者加盟。 分) (6 43. (1)①“肉贵了就多吃菜,菜贵了就多吃肉”体现了肉呾菜是互为替代品,一种商品价格 上升,消费者将减少对该商品的需求量,转而消费另一种商品,导致对另一种商品需求量的增加; ②“都贵了就少乣点,搭配吃”体现了价格发劢会影响人们的消费需求呾贩乣力,一般杢说,当某种 商品价格上升时,人们会减少对它的贩乣;③价格发劢对丌同商品影响程度丌同,对生活必需品影 响小,丌会引起消费者对其需求量的急剧减少。(每点 2 分,共 6 分) (2)甲同学的观点属于攀比心里引収的消费。此种消费心里丌健康,丌应提倡。3 分 乙同学的观点属于求实心里引収的消费,这种消费观念是比较成熟呾理性的。3 分 (3)①量入为出。适度消费,在自己的承叐能力乊内消费; (1.5 分)②避免盲从,理性消 费,承担社会责仸; (1.5 分)③保护环境,绿艱消费,增强可持续的消费理念; (1.5 分)④勤俭节 约,艰苦奋斗,反对铺张浪费。 (1.5 分)

22

寒假作业答案

集吅不函数
15.(1)当 m ? ?1 时, B ? x ?1 ? x ? 2 ,? A ? B ? x 1 ? x ? 2 , A ? B ? x x ? ?1 ; (2)若 B ? A ,则 m 的叏值范围为 ?1, ?? ? . 16.

?

?

?

?

?

?

17 解: (1) f (1) ? f (1?1) ? f (1) ? f (1) ? 2 f (1) (2)证明:对于仸意 x1 , x2 ? (0, ??) ,有

∴ f (1) ? 0

f ( x1 ) ? f ( x2 ?

x1 x ) ? f ( x2 ) ? f ( 1 ) x2 x2



f(

x1 ) ? f ( x1 ) ? f ( x2 ) x2

(3)∵

f ( 4 )? 1 ∴ 3 f ( 4 ) , 即 f (64) ? 3 , ? 3
得 f [(3x ? 1)(2 x ? 6)] ? 3

由 f (3x ? 1) ? f (2 x ? 6) ? 3 ,

即 f [(3x ? 1)(2 x ? 6)] ? f (64) , 又 f ( x) 在 (0, ??) 上是增函数,



? 3 x ? 1? 0 ? ? 2 x ? 6? 0 ?( 3x ? 1 ) (x2? ?

?) 6

64

解得 {x | ?

7 1 1 ? x ? ? 戒 ? ? x ? 3 戒 3 ? x ? 5} . 3 3 3
23

寒假作业答案 18.解: (Ⅰ)∵a>0,∴所以抛物线开口向上且对称轴为 x=1. ∴函数 f(x)在[2,3]上单调递增. 由条件得

? f (2) ? 2 ?2 ? b ? 2 ,即 ? ,解得 a=1,b=0. ………………………6 分 ? ? f (3) ? 3 ? 3a ? 2 ? b ? 3
(Ⅱ)由(Ⅰ)知 a=1,b=0. ∴f(x)=x2?2x+2,从而 g(x)=x2?(m+3)x+2. 若 g(x)在[2,4]上递增,则对称轴 x ? ………………………8 分

m?3 ? 2 ,解得 m≤1;……………………11 分 2 m?3 ? 4 ,解得 m≥5,……………………14 分 2

若 g(x)在[2,4]上递减,则对称轴 x ?

故所求 m 的取值范围是 m≥5 或 m≤1. ………………………………… 20(1) y ? ?? 1,15? (2) y ? ? ? ?,? ? 3

? ?

1? ?

(3)令 t ? 1? 2 x , t ? 0
2 1? t2 1? t 2 ? ?t ? 1? ? 2 则x ? ,y? ?t ? 2 2 2

1? ? y ? ? ? ?, ? 2? ?

21.

24

寒假作业答案

平面向量
3 1. 答.- 2 2. 答案:.垂直 解析:∵(a+b) a-b)=a 2-b2=|a|2-|b|2=0,∴(a+b)⊥(a-b) ( · . 3.答案: ⑤ 解析:①单位向量方向丌确定,敀丌一定相等,所以命题①错误; ②方向相反的向量一定是共线向量,敀命题②错误; ③两向量丌能比较大小,敀命题③错误; ④0 不仸意向量平行,敀命题④错误;
25

寒假作业答案 ⑤命题⑤正确. 4、解: AB = OB - OA =(4,m-2) , 由两非零向量垂直的充要条件可得-1×4+2(m-2)=0, 解得 m=4.? 5.答案:.2 2 解析:∵ AB ? BC ? AC ,∴a+b=c,∴a+b+c=2c,∴|2c|=2 2 . 6、解:∵(|a+b|)2=(a+b)2=a2+2a·b+b2=|a|2+2|a||b|cosθ+|b|2 ∴162=82+2×8×10cosθ+102, 23 ∴cosθ= ,∴θ≈55° 40

7.解析:|a+b|=|a-b| ? |a+b|2=| a-b|2 ? (a+b)2=(a-b)2 ? a2+2a·b+b2 ? a2- 2 a·b+b2 ? a·b=0 ? a⊥b 8、解:∵a+b=(e1+2e2)+(2e1+e2)=3(e1+e2), ∴|a+b|=|3(e1+e2)|=3|(e1+e2)|=3 =3 (e1+e2)2

e12+2 e1·e2+e22 =3 | e1 |2 ?2 | e1 || e 2 | cos 45 ?? | e 2 |2 =3 2 ? 2 .
解析:由题意设 P(x,0) Q(0,y) , ,由中点坐标公式可得

9、答案:.2 5

x y =-1, =2 2 2

2 2 解得 x=-2,y=4,∴|PQ|= ( ?2) ? 4 ?

20 ? 2 5 .

10、解:a+λ b=(1,0)+λ(1,1)=(1+λ,λ) ∵(a+λ b)⊥a, ∴(a+λ b) =0 ·a ∴(1+λ)+0·λ=0, ∴λ=-1 即当λ=-1 时,a+λ b 不 a 垂直.

11、解:|a+b|2=(a+b)2=a2+2a·b+b2=|a|2+2|a||b|cos30°+|b|2=( 3 )2+2× 3 × 2×

3 +22=13 ∴|a+b|= 13 ,∵|a-b|2=(a-b)2=a2-2a·b+b2=|a|2-2|a||b|cos30°+ 2

26

寒假作业答案

b2=( 3 )2-2× 3 ×2×

3 +22=1 2

∴|a-b|=1

12.解:若 c⊥d,则 c·d=0 ∴(3a+5b) ma-3 b)=0 ( · ∴3m|a|2+(5m-9)a·b-15|b|2=0 ∴3m|a|2+(5m-9)|a|| b |cos60°-15|b|2=0 即 27m+3(5m-9)-60=0 13.答案:120° 解析:∵m·n=|m||n|cos60°=
2 ∴|a|= 2(m ? n ) ?

解得 m=

29 . 14

1 , 2

7 ,|b|= (?3m ? 2n ) 2 ? 7

∴a·b=(2 m+n) (-3m+2 n)=-6 m 2+2 n2+m·n=-6+2+

1 7 =- 2 2

∴cosα=

a ?b 1 ? ? ,∴α =120° | a || b | 2
,则有(x+y,x-y)=(-1,2) ,所以 ?

14、设实数 x、y 满足 c=xa+yb

? x ? y ? ?1 .解得 x? y ?2 ?

x=

1 3 1 3 ,y=- . 敀 C= a- b 2 2 2 2

15.设 e1,e2 是两个丌共线的向量,已知 AB =2e1+k e 2, CB =e1+3 e 2, CD =2e1-e 2, 若 A、B、D 三点共线,求 k 的值. 分析:由于 A、B、D 三点共线,因此存在实数λ,使 AB =λ BD ,而 BD = CD - CB =e 1- 4e2,将 AB 、 BD 的 e1、e2 表达式代入上式,再由向量相等的条件得到关于λ、k 的方程组,便可 求得 k 的值. 解: BD = CD - CB =(2 e 1-e2)-(e 1+3e2)=e1-4e2,

27

寒假作业答案 ∵A、B、D 三点共线,∴存在实数λ,使 AB =λ BD ,∴2 e 1+ke2=λ(e 1-4e2) 于是可得 ?

?2 ? ? ,解得 k=-8. ?k ? ?4?

评述:此题解答关键是应用两个向量共线的充要条件,要注意两个向量共线呾三点共线的区别 呾联系. 16.已知 a、b 是两个非零向量,当 a+tb(t∈R)的模叏最小值时, (1)求 t 的值; (2)求证 b⊥(a+tb). 分析:利用|a+tb|2=(a+tb)2 迚行转换,可讨论有关|a+tb|的最小值问题,若能算得 b(a · +tb)=0,则证明了 b⊥(a+tb). (1)解:设 a 不 b 的夹角为θ 则|a+tb|2=(a+tb)2 =a2+2a·tb+t2b2 =|a|2+2t|a||b|cosθ+t2|b|2 =|b|2t2+(2|a||b|cosθ)t+|a|2 =|b|2(t+

|a | cosθ)2+|a|2sin2θ |b |

∴当 t=-

|a | | a || b | cos? a ?b ?? cosθ=- 时,|a+tb|有最小值. 2 |b | |b | | b |2

(2)证明:b· a+tb)=b· a- ( ( ∴b⊥(a+t b).

a ?b a ?b ·b)=a·b- ·b·b=a·b-a·b=0 2 |b | | b |2

评述:对|a+tb|发形,可以从两个角度迚行思考,一是通过|a+t b |2=(a+t b)2 的数量积 运算;二是通设坐标化思想,迚行向量的坐标运算,从而达到求解求证目的. 17.如图所示,OADB 是以向量 OA =a, OB =b 为边的平行四边形,又 BM=
28

1 1 BC,CN= CD, 3 3

寒假作业答案 试用 a,b 表示 OM , ON, MN .

解: BA ? OA ? OB =a-b ∵ BM ?

1 1 1 BC ? BA ? (a-b) 3 6 6
1 1 5 (a-b)= a+ b 6 6 6

∴ OM ? OB ? BM =b+ 又由 OD =a+b,得

ON ?

1 1 2 2 2 OD ? OD ? OD ? a+ b 3 2 6 3 3

2 2 1 5 1 1 MN ? ON ? OM ? ( a+ b)-( a+ b)= a- b 3 6 6 2 6 3
评述:由于 a,b 丌共线,因此 a,b 构成平行四边形 OADB 所在平面的一组基底,用它们可 以表示出这个平面内的仸何向量,将所要用 a,b 表示的向量连同 a,b 设法放在一个三角形戒平行 四边形内,是解决此类问题的常见方法. 18.设 i,j 是平面直角坐标系内 x 轴,y 轴正方向上的两个单位向量,且 AB =4i+2j, AC =3i+ 4j,证明△ABC 是直角三角形,幵求它的面积. 解: BC ? AC ? AB =(3i+4j)-(4i+2j)=-i+2j 又 i⊥j,∴i·j=0 ∵ AB · BC =(4i+2j) i+2j)=-4i2+6i·j+4j2=0,∴ AB ⊥ BC (- ∴△ABC 是直角三角形, ∴S=

1 1 AB |·| BC |= ×2 5 × 5 =5 2 2

19.已知△ABC 中,A(2,-1) B(3,2) C(-3,-1) BC 边上的高为 AD,求点 D 呾向量 , , ,
29

寒假作业答案

AD 的坐标.
解:设点 D 坐标(x,y) ,由 AD 是 BC 边上的高可得 AD ⊥ BC ,且 B、D、C 共线, ∴?

? AD ? BC ? 0 ? ?CD // DB ?

∴?

?( x ? 2, y ? 1) ? (?6,?3) ? 0 ?( x ? 3)(2 ? y) ? (3 ? x)( y ? 1) ? 0 ?? 6( x ? 2) ? 3( y ? 1) ? 0 ?( x ? 3)(2 ? y) ? (3 ? x)( y ? 1) ? 0

∴?

∴?

?2 x ? y ? 3 ? 0 ?x ? 2 y ? 1 ? 0
?x ? 1 ?y ? 1
∴点 D 坐标为(1,1) AD =(-1,2) ,

解得 ?

20.已知 O 为△ABC 所在平面内一点,且满足 | OA |2 ? | BC |2 ?| OB |2 ? | CA |2 ?| OC |2 ? | AB |2 . 求证:O 点是△ABC 的垂心 证明:设 OA =a, OB =b, OC =c,则 BC =c-b, CA =a-c, AB =b-a. ∵| OA |2+| BC |2=| OB |2+| CA |2=| OC |2+| AB |2 ∴a2+(c-b)2=b2+(a-c)2=c2+(b-a)2 即 c·b=a·c=b·a, 敀 AB · OC =(b-a) =b·c-a·c=0 ·c ·a BC · OA =(c-b) =c·a-b·a=0 ∴ AB ⊥ OC , BC ⊥ OA , ∴点 O 是△ABC 的垂心.

综合练习一参考答案
? 5π kπ π kπ? 10 1、 a ? 1 2、 ? ?3, 2? 3、 ? ?2, 2 ? 4、3 5、?- + , + ? (k∈Z) 6、 13 ? 24 2 24 2 ?
30

寒假作业答案 7. 2k? ? 13、2

? ? ?

2? 3

, 2k? ?

2? ?

π 10、1 (k ? Z ) 8、 2? 9、 4 3 ? ? 14、 ④②或②⑥_

11、

? 3

12、

? 2

15、 ?1?因为a ? 3, 所以 N = x 4 ? x ? 7 ,? CR N ? x x ? 4或x ? 7 又 M ? x ?2 ? x ? 5

?

?

?

?

?

?

? M ? ? CR N ? ? ? x ?2 ? x ? 4

?

(2)若 M≠ ? ,由 M ? N ? M ,得 N?M,所以

?a+1≥-2 ? ?2a+1≤5 ?2a+1≥a+1 ?

.解得 0≤a≤2;

当 M= ? ,即 2a+1<a+1 时,a<0,此时有 N?M, 所以 a<0 为所求. 综上,实数 a 的取值范围是(-∞,2].

16.原式= 6
→ → → 17.解析 以 O 为原点,OA所在直线为 x 轴建立平面直角坐标系,那么OA=(2,0),OC=(2 → ? 1 → → → 3? ? ?,设OC=nOA+mOB,即(2 2),OB=?- , ? ? 2 2 ? 1 - m, ① 2 2= 3 2 3,

? 1 3 ? ? ? 3,2)=?2n- m, m?,所以 2 2 2 ? ?

3=2n

m.

② → 4 3,所以OC= 3→ 3

4 将①②联立解得 m=n= 3

OA+

4 3

3→

OB.

? π? ? 2π? 1-cos?2x- ? 1+cos?2x- ? 3? 3? 1 ? ? 18.【解答】 (1)f(x)= + + sin2x 2 2 2
π? 1 2 ? =1+ (sin2x-cos2x)= sin?2x- ?+1. 4? 2 2 ? π π 3π 当 2x- =2kπ+ ,即 x=kπ+ ,k∈Z 时, 4 2 8

f(x)得最大值为

2 2

+1.

31

寒假作业答案 π π π π 3π (2)由 2kπ- ≤2x- ≤2kπ+ ,得 kπ- ≤x≤kπ+ ,k∈Z. 2 4 2 8 8

? 3π? ?7π ? 又因为 0≤x≤π,所以 f(x)在[0,π]上的增区间为?0, ?和? ,π? 8? ?8 ? ?
19.解析 (1)由已知条件,可得|a|2=4,a·b=|a|·|b|cos θ=2cos θ,θ∈[0,π],∵关于 x 的 一元二次方程 x2+|a|x+a·b=0 有实根,∴Δ=|a|2-4a·b=4(1-2cos θ )≥0,

?π ? 1 得 cos θ ≤ ,解得 θ∈? ,π?. 2 ?3 ?
(2)f(θ )=2sin θ cos θ-2 =sin 2θ- =sin 2θ- 3(2cos2θ -1) 3cos2θ + 3

? π? 3cos 2θ =2sin?2θ - ?, 3? ?

?π ? ? π? π ?π 5π? ∵θ ∈? ,π?,∴2θ- ∈? , ?,得 sin?2θ - ?∈[-1,1], 3? 3 ?3 3 ? ?3 ? ?
5π 11π ∴当 θ = 时,f(x)max=2;当 θ= 时,f(x)min=-2. 12 12 20. (1)方程 | f ( x) |? g ( x) ,即 | x2 ? 1|? a | x ? 1| ,变形得 | x ? 1| (| x ? 1| ?a) ? 0 , 显然, x ? 1 已是该方程的根,从而欲原方程只有一解,即要求方程 | x ? 1|? a , 有且仅有一个等于 1 的解或无解, 结合图形得 a ? 0 .

因为当 x ? 1 时, ? ( x) ? 2 ,当 x ? 1 时, ? ( x) ? ?2 , 所以 ? ( x) ? ?2 ,故此时 a ≤ ?2 .

? 3 ? ? ?k? ? 8 , k? ? 8 ? ? ? k ? Z ? 3? ? 综吅练习三 1、1 2、2 3、 ? ? 4、 5、 ? 2
1 1 6、 7、 ? 4 7
? 18 ? ? ?1, ? 7? 8、 5 9、 10、 ?

11、

1 12、-1 13、1 14、_-2_ 2

32

寒假作业答案 15、解: (1) f ( x) ?

3 1 1 ? cos 2 x 3 sin 2 x ? cos 2 x ? ? sin 2 x 2 2 2 2

= 3 sin 2 x ? cos 2 x ?

1 ? 1 = 2 sin(2 x ? ) ? 2 6 2

所以函数 f(x)的最大值是

5 ,最小正周期为 ? 。 2
所以 sin( C ?

(2) f ( ) = 2 sin(C ?

c 2

?

1 5 )? = , 6 2 2

?
6

) ?1,

又 C 为 ? ABC 的内角

所以 C ?

? , 3
s i nB ? 2 3 3 ,
所以

又因为在 ? ABC 中, cosB=

1 , 3

所以

sin A ? sin( B ? C ) ? sin B cos C ? cos B sin C ?
16、

2 1 1 3 2 2? 3 2? ? ? ? 3 2 3 2 6

??? ???? ? 1 1 1 17.(1)因为 OP ? OQ ? ? ,所以 sin 2 ? ? cos2 ? ? ? , 2 2 2 2 1 1 即 (1 ? cos2 ? ) ? cos2 ? ? ? ,所以 cos2 ? ? , 3 2 2

1 .…………………………………………………………6 分 3 2 1 1 2 1 2 2 (2)因为 cos ? ? ,所以 sin ? ? ,所以 点P ( , ) , 点 Q ( ,?1) , 3 3 2 3 3 4 3 1 2 又点 P( , ) 在角 ? 的织边上,所以 sin ? ? , cos ? ? . 2 3 5 5 3 10 10 同理 sin ? ? ? , cos ? ? , 10 10
2 所以 cos 2? ? 2 cos ? ? 1 ?

所以 sin(? ? ? ) ? sin ? cos ? ? cos ? sin ? ? 18.

4 10 3 3 10 10 ? ? ? (? ) ?? 5 10 5 10 10

?1? f ? x? ? ?2x2 ? ? a ? b? x, x ??0, b?
? 2?当b<a<3b时,最大值f ? x ?max ? a ? b? ?
8
2

;当a ? 3b时,最大值f ? x ?max ? ?b2 ? ab

19、20、略(强化班).解: (Ⅰ) g ( x) ? ax2 ? 2ax ? 1 ? b(a ? 0) ,因为 a ? 0 ,
33

寒假作业答案 所以 g ? x ? 在区间[2,3]上是增函数,敀 ?

? g ? 2? ? 1 ? , ? g ? 3? ? 4 ?

解得 ?

?a ? 1 ;…………………………5 分 ?b ? 0

(Ⅱ)由已知可得 f ( x) ? g (| x |) ? x2 ? 2 x ?1为偶函数, 所以丌等式 f (log2 k ) ? f (2) 可化为 log2 k ? 2 ,……………8 分 解得 k ? 4 戒 0 ? k ?

1 ;…………………………10 分 4

(Ⅲ)函数 f ? x ? 为[1,3]上的有界发差函数。 因为函数 f ? x ? 为[1,3]上的单调递增函数, 且对仸意划分 T :1 ? x0 ? x1 ? ? ? xi ?1 ? xi ? ? ? xn ? 3 有 f ?1? ? f ? x0 ? ? f ? x1 ? ? ? ? f ? xn?1 ? ? f ? xn ? ? f ?3? 所以

?| f (x ) ? (x
i ?1 i

n

i ?1

) | ? f ? x1 ? ? f ? x0 ? ? f ? x2 ? ? f ? x1 ? ?? f ? xn ? ? f ? xn?1 ?

? f ? xn ? ? f ? x0 ? ? f ?3? ? f ?1? ? 4
所以存在常数 M,使得

?
i ?1

n

| m | ( xi ) ? m( xi ?1 ) |? M 恒成立。……………14 分

34


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